If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5j^2+36j+7=0
a = 5; b = 36; c = +7;
Δ = b2-4ac
Δ = 362-4·5·7
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-34}{2*5}=\frac{-70}{10} =-7 $$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+34}{2*5}=\frac{-2}{10} =-1/5 $
| 15=6l-3l | | -3(n+6)+10=-6 | | 7(h+3)=6(h-3 | | Y1=3(2x-5) | | (x)/5=5+(x-4)/(2) | | 13=5f+8f | | 600+x(15)=2,400 | | -3a+24+6a=2a-5a | | 18=a÷2 | | -4(8-2x)=-88 | | 51x+7=-10 | | 0=5o+o | | 4+n/14=2 | | 35-2x=13+9x | | x^2-26x+35=0 | | m-6/10=5 | | 5/x+7=-10 | | 3x+5-2x=78 | | y=372,000(1+.05)^8 | | (s-6)=20 | | -12-16k-9=15-20k | | 45n=12n+130 | | 1=0.3x-0.9x-35 | | -(3/4)x=12 | | 4n^2+15n+11=0 | | 16-2u=-u | | 7+6n=2n+11 | | 17w+19=19-16w | | (3+2y)=4 | | -5(7b-3)=120 | | -2/9b=1/3b+7 | | -6m=-4m-10 |